Even after reading many articles on Banker’s algorithm and Europe’s deadlock several times, I couldn’t get what they were about.
I didn’t understand how an algorithm could have solved with the debt crisis.
I realized I would have to go back to the basics of banking and figure out answers to these:
How do banks work? How do banks decide the loan amount? What is the Banker’s algorithm?
We will begin with the Banker’s algorithm, which will help you understand banking and “Deadlock.”
The Banker’s algorithm sometimes referred to as avoidance algorithm or Deadlock algorithm was developed by Edsger Dijkstra (another of Dijkstra’s algorithms!).
It tests the safety of allocation of predetermined maximum possible resources and then makes states to check the deadlock condition. (Wikipedia)
Let’s say you’ve got three friends (Chandler, Ross, and Joey) who need a loan to tide them over for a bit.
You have $24 with you.
Chandler needs $8 dollars, Ross needs $13, and Joey needs $10.
You already lent $6 to Chandler, $8 to Ross, and $7 to Joey.
So you are left with $24 – $21 (6+8+7) = $3
Even after giving $6 to Chandler, he still needs $2. Similarly, Ross needs $5 more and Joey $3.
Until they get the amount they need, they can neither do whatever tasks they have to nor return the amount they borrowed. (Like a true friend!)
You can pay $2 to Chandler, and wait for him to get his work done and then get back the entire $8.
Or, you can pay $3 to Joey and wait for him to pay you back after his task is done.
You can’t pay Ross because he needs $5 and you don’t have enough.
You can pay him once Chandler or Joey returns the borrowed amount after their work is done.
This state is termed as the safe state, where everyone’s task is completed and, eventually, you get all your money back.
Knowing Ross needs $10 urgently, instead of giving $8, you end up giving him $10.
And you are left with only $1.
In this state, Chandler still needs $2 more, Ross needs $3 more, and Joey still needs $3 more, but now you don’t have enough money to give them and until they complete the tasks they need the money for, no money will be transferred back to you.
This kind of situation is called the Unsafe state or Deadlock state, which is solved using Banker’s Algorithm.
Let’s get back to the previous safe state.
You give $2 to Chandler and let him complete his work.
He returns your $8 which leaves you with $9. Out of this $9, you can give $5 to Ross and let him finish his task with total $13 and then return the amount to you, which can be forwarded to Joey to eventually let him complete his task.
(Once all the tasks are done, you can take Ross and Joey to Central Perk for not giving them a priority.)
The goal of the Banker’s algorithm is to handle all requests without entering into the unsafe state, also called a deadlock.
The moneylender is left with not enough money to pay the borrower and none of the jobs are complete due to insufficient funds, leaving incomplete tasks and cash stuck as bad debt.
It’s called the Banker’s algorithm because it could be used in the banking system so that banks never run out of resources and always stay in a safe state.
For the banker’s algorithm to work, it should know three things:
So we need MAX and REQUEST.
If REQUEST is given MAX = ALLOCATED + REQUEST
NEED = MAX – ALLOCATED
A resource can be allocated only for a condition.
REQUEST<= AVAILABLE or else it waits until resources are available.
Let ‘n’ be the number of processes in the system and ‘m’ be the number of resource types.
Where you have 4 processes, and 3 resources (A, B, C) to be allocated.
| Process | Allocated | Maximum | Available | Need (Maximum Allocated) | ||||||||
| A | B | C | A | B | C | A | B | C | A | B | C | |
| P1 | 0 | 1 | 0 | 7 | 5 | 3 | 3 | 3 | 2 | 7 | 4 | 3 |
| P2 | 2 | 0 | 0 | 3 | 2 | 2 | 1 | 2 | 2 | |||
| P3 | 4 | 0 | 1 | 9 | 0 | 4 | 5 | 0 | 3 | |||
| P4 | 2 | 1 | 1 | 2 | 2 | 2 | 0 | 1 | 1 | |||
Need P2<Available, so we allocate resources to P2 first.
After P2 completion the table would look as
| Process | Allocated | Maximum | Available | Need (Maximum Allocated) | ||||||||
| A | B | C | A | B | C | A | B | C | A | B | C | |
| P1 | 0 | 1 | 0 | 7 | 5 | 3 | 5 | 3 | 2 | 7 | 4 | 3 |
| P3 | 4 | 0 | 1 | 9 | 0 | 4 | 5 | 0 | 3 | |||
| P4 | 2 | 1 | 1 | 2 | 2 | 2 | 0 | 1 | 1 | |||
Need P4<Available, so we allocate resources to P4.
After P4 completion
| Process | Allocated | Maximum | Available | Need (Maximum Allocated) | ||||||||
| A | B | C | A | B | C | A | B | C | A | B | C | |
| P1 | 0 | 1 | 0 | 7 | 5 | 3 | 7 | 4 | 3 | 7 | 4 | 3 |
| P3 | 4 | 0 | 1 | 9 | 0 | 4 | 5 | 0 | 3 | |||
And P3 will be allocated before P1, which gives us the sequence P2, P4, P3, and P1 without getting into deadlock.
A state is considered safe if it is able to finish all processing tasks.
#include <iostream>
#define MAX 20
using namespace std;
class bankers
{
private:
int al[MAX][MAX],m[MAX][MAX],n[MAX][MAX],avail[MAX];
int nop,nor,k,result[MAX],pnum,work[MAX],finish[MAX];
public:
bankers();
void input();
void method();
int search(int);
void display();
};
bankers::bankers()
{
k=0;
for(int i=0;i<MAX;i++)
{
for(int j=0;j<MAX;j++)
{
al[i][j]=0;
m[i][j]=0;
n[i][j]=0;
}
avail[i]=0;
result[i]=0;
finish[i]=0;
}
}
void bankers::input()
{
int i,j;
cout << "Enter the number of processes:";
cin >> nop;
cout << "Enter the number of resources:";
cin >> nor;
cout << "Enter the allocated resources for each process: " << endl;
for(i=0;i<nop;i++)
{
cout<<"\nProcess "<<i;
for(j=0;j<nor;j++)
{
cout<<"\nResource "<<j<<":";
cin>>al[i][j];
}
}
cout<<"Enter the maximum resources that are needed for each process: "<<endl;
for(i=0;i<nop;i++)
{
cout<<"\nProcess "<<i;
for(j=0;j<nor;j++)
{
cout<<"\nResouce "<<j<<":";
cin>>m[i][j];
n[i][j]=m[i][j]-al[i][j];
}
}
cout << "Enter the currently available resources in the system: ";
for(j=0;j<nor;j++)
{
cout<<"Resource "<<j<<":";
cin>>avail[j];
work[j]=-1;
}
for(i=0;i<nop;i++)
finish[i]=0;
}
void bankers::method()
{
int i=0,j,flag;
while(1)
{
if(finish[i]==0)
{
pnum =search(i);
if(pnum!=-1)
{
result[k++]=i;
finish[i]=1;
for(j=0;j<nor;j++)
{
avail[j]=avail[j]+al[i][j];
}
}
}
i++;
if(i==nop)
{
flag=0;
for(j=0;j<nor;j++)
if(avail[j]!=work[j])
flag=1;
for(j=0;j<nor;j++)
work[j]=avail[j];
if(flag==0)
break;
else
i=0;
}
}
}
int bankers::search(int i)
{
int j;
for(j=0;j<nor;j++)
if(n[i][j]>avail[j])
return -1;
return 0;
}
void bankers::display()
{
int i,j;
cout<<endl<<"OUTPUT:";
cout<<endl<<"========";
cout<<endl<<"PROCESS\t ALLOTED\t MAXIMUM\t NEED";
for(i=0;i<nop;i++)
{
cout<<"\nP"<<i+1<<"\t ";
for(j=0;j<nor;j++)
{
cout<<al[i][j]<<" ";
}
cout<<"\t ";
for (j=0;j<nor;j++)
{
cout<<m[i][j]<<" ";
}
cout<<"\t ";
for(j=0;j<nor;j++ )
{
cout<<n[i][j]<<" ";
}
}
cout<<"\nThe sequence of the safe processes are: \n";
for(i=0;i<k;i++)
{
int temp = result[i]+1 ;
cout<<"P"<<temp<<" ";
}
cout<<"\nThe sequence of unsafe processes are: \n";
int flg=0;
for (i=0;i<nop;i++)
{
if(finish[i]==0)
{
flg=1;
}
cout<<"P"<<i<<" ";
}
cout<<endl<<"RESULT:";
cout<<endl<<"=======";
if(flg==1)
cout<<endl<<"The system is not in safe state and deadlock may occur!!";
else
cout<<endl<<"The system is in safe state and deadlock will not occur!!";
}
int main()
{
cout<<" DEADLOCK BANKER’S ALGORITHM "<<endl;
bankers B;
B.input ( );
B.method ( );
B.display ( );
} If you understood the process, congratulations on being a non-certified banker of the nation!
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