For test case \(1\):
The possible arrays \(V\) that will make Bob happy are: \([ 1, 2, 3 ], [ 1, 2, 4 ], [ 1, 3, 4 ]\). Let us try calculating the value \(( ( ( M \mod V[ 0 ] ) \mod V [ 1 ] ) ...\mod V [ N - 1 ] )\) with \(M = 13\), for various shufflings of the array \([ 1, 2, 3 ]\):

\([ 2, 1, 3 ] \rightarrow (((13 \mod 2) \mod 1) \mod 3) = ((1 \mod 1) \mod 3) = (0 \mod 3) = 0\)
\([ 3, 2, 1 ] \rightarrow (((13\mod 3) \mod 2) \mod 1) = ((1 \mod 2) \mod 1) = (1 \mod 1) = 0\)
\([ 1, 2, 3 ] \rightarrow (((13 \mod 1) \mod 2) \mod 3) = ((0 \mod 2) \mod 3) = (0 \mod 3) = 0\)

Similarly, the other shufflings of \([ 1, 2, 3 ]\) will give the result \(0\) for\(M = 13\). Similar invariance will hold for all values of \(M\) for all three arrays. Therefore, the answer is \(3\).

For test case \(2\):
The only \(V\) that can be made is \([ 1, 2, 3 ]\), which will make Bob happy. Thus the answer is \(1\).

For test case \(3\):
There are \(11\) different \(V\) that make Bob happy. Some of them are: \([ 1, 5, 6 ], [ 1, 3, 4 ], [ 1, 2, 3 ]\). Thus the answer is \(11\).