You are given current status of light bulb(ON/OFF) and number N.
The switch of the bulb is flipped X times. where X is total number of divisors of N.
determine if bulb is ON or OFF
INPUT FORMAT:
Input consist of two space separated integers A and N
if bulb is ON A is 1 otherwise 0
OUTPUT FORMAT:
If Bulb is glowing print ON otherwise print OFF.
CONSTRAINT
1 <= N <= 10^18
0 <= A <= 1
total divisors of 5 is 2 so switch will be flipped two times and finally the bulb will be OFF.